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Q.

A mixture of methane and ethene in the mole ratio X : Y has a mean molecular weight = 20. What would be the mean molecular weight if the same gases are mixed in the ratio Y : X

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a

22

b

24

c

20.8

d

19

answer is B.

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Detailed Solution

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Mol.wt. of CH₄ = 16

Mol.wt. of C₂H₄ = 28

$∴ 20 = \frac{16 x + 28 y}{x + y}$

$x = 2 y$

In the gaseous mixture when the mole ratio of ${CH}_{4}$ and $C_{2} H_{4}$ is $y : x$

Then the avg.mol.wt. = $\frac{16 y + 28 x}{x + y} = \frac{16 y + 56 y}{3 y}$

$= \frac{72 y}{3 y}$

= $24$

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