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Q.

A mixture of methane and ethylene in the volume ratio x : y has a total volume of 30ml. On complete combustion it gave 40ml of CO₂. If the ratio had been y : x, instead of x : y, what volume of CO₂ could have been obtained?

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a

50ml

b

100ml

c

25ml

d

75ml

answer is A.

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Detailed Solution

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${CH}_{4} + 2 O_{2} \to {CO}_{2} + 2 H_{2} O C_{2} H_{4} + 3 O_{2} \to 2 {CO}_{2} + 2 H_{2} O Ratio of volumes of {CO}_{2} liberated = 1 : 2 given, x + y = 30 ml, Total volumes of {CO}_{2} = 40 ml Hence, x : y = 20 : 10 = 2 : 1 If x : y = 1 : 2, Then Ratio of volumes of {CO}_{2} = 1 : 4 ∴ Total volume of {CO}_{2} = 10 + 40 = 50 ml$

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