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A mixture of $N_{2}$ and $H_{2}$ in the molar ratio. 1:3 attains equilibrium when 50% of mixture has reacted. If P is the total pressure of the mixture the partial pressure of $N H_{3}$ formed is P/Y. Then the value of Y is ____

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answer is B.

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Detailed Solution

Out of 4 moles 2 moles are reacted
$∴ 1 - x + 3 - 3 x = 2 \Rightarrow x = 0.5$
Total moles at $e q = (1 - x) (3 - 3 x) + 2 x = 3$
$P_{N H_{3}} = \frac{1}{3} \times p = \frac{p}{3}$

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