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Q.

A mixture of N₂ and H₂ in the mole ratio 1 : 3 is allowed to attain equilibrium when 50% of mixture has reacted. If P is the equilibrium pressure, then partial pressure of NH₃ formed is:

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a

P/4

b

P/6

c

P/2

d

P/3

answer is C.

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Detailed Solution

$\underset{1 - x}{\underset{1}{N_{2}}} + \underset{3 - 3 x}{\underset{3}{3 H_{2}}} ⇌ \underset{2 x}{\underset{0}{2 {NH}_{3}}}$
$∵$ 50% mixture reacts
$\begin{array}{l} ∴ 1 - x + 3 - 3 x = \frac{4}{2} = 2 \\ x = 0 .5 \\ ∴ P_{{NH}_{3}}^{1} = P_{T} \times mf of {NH}_{3} \\ = \frac{P \times 2 \times 0 .5}{(4 - 0 .5 \times 2)} = \frac{P}{3} \end{array}$

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