A mixture of one mole each of $H_{2}$ , He and $O_{2}$ each are enclosed in a cylinder of volume V at temperature T . If the partial pressure of $H_{2}$ is 2 atm, the total pressure of the gases in the cylinder is

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22 atm

14 atm

6 atm

38 atm

answer is C.

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Detailed Solution

According to Dalton’s law of partial pressure $P_{i} = x_{i} \times P_{t}$
$P_{t} = (\frac{{nH}_{2} + nHe + {nO}_{2}}{{nH}_{2}}) P_{i} P_{t} = \frac{3}{1} \times 2 = 6 atm .$

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