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Q.

A mixture of the metals A and B where equivalent weights are 12 and 9 displace H2 from an acid. If 0.39 g of mixture displace 448 cc of hydrogen at STP. The mixture contains

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a

0.27 g A

b

0.27 g B

c

0.12 g A

d

0.12 g B

answer is A, C.

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Detailed Solution

0.39-x12+x9=Mass of 448mL of H2

039-x3+4x36=0.04

(0.39 − x)3 + 4x = 1.44

1.17 + x = 1.44 

x = 0.27 grams

Hence, Mass of B = 0.27 grams

Mass of A = 0.12 grams

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