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A mixture of two immiscible liquids A and B, having vapour pressure in pure state obeys the following relationship if X_A and X_B are mole fractions of A and B in vapour phase over the solution

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$P'_{A} = P_{M} X'_{A}$

$\frac{P'_{A}}{P'_{B}} = \frac{W_{A} \times {Mw}_{B}}{{Mw}_{A} \times W_{B}}$

If $P'_{A} > P'_{B}$ then $X'_{A} < X'_{B}$

If $P'_{A} > P'_{B}$ then $n_{A} > n_{B}$

answer is A, B, D.

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Detailed Solution

For immiscible liquids

$P'_{A} = P_{M} \cdot X'_{A}; P'_{B} = P_{M} \cdot X'_{B} ∴ \frac{P'_{A}}{P'_{B}} = \frac{X'_{A}}{X'_{B}} = \frac{n_{A}}{n_{B}} = \frac{W_{A} \times {Mw}_{B}}{{Mw}_{A} \times W_{B}} If P_{A}^{'} > P'_{B}, then n_{A} > n_{B}$

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