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Q.

A mixture of two immiscible liquids nitrobenzene and water boiling at $99^{0} C$ has a partial vapour pressure of water 733 mm and that of nitrobenzene 27 mm. Calculate the ratio of the masses of water to the nitrobenzene in distillate ?

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Detailed Solution

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$P = P_{M} \times x_{A}$

$27 = 760 \times \frac{w_{2} / 123}{\frac{w_{1}}{18} + \frac{w_{2}}{123}}$ for nitrobenzene $\frac{w_{1}}{w_{2}} = 4$

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