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A mixture of $(Z n^{+ 2}, M n^{+ 2}, N i^{+ 2}, A g^{+})$ radicals on reaction with $N H_{4} C l + N H_{4} O H + H_{2} S$ gas gives ‘X’ no. of metal sulphide precipitates and on further reaction with $H C l$ gives ‘y’ no.of metal chlorides as precipitates . Find the value of (x+y)

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answer is 5.

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Chlorides of above metal ions are soluble only Zns and MnS Soluble in HCl so y=1

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