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Q.

A mixture of H2(g),N2(g) and O2(g) occupying 10 mL underwent reaction so as to form H2O2(l) and N2H2(g) as the only products causing the volume to contract by 6 mL. The remaining mixture was passed through Pyrogallol causing a contraction of 1 mL. To the remaining mixture excess H2 was added and the above reaction was repeated, causing a reduction in volume of 1 mL. Assuming no older products to be forming calculate the volume of H2 (in mL in the initial mixture.

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answer is 4.

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Detailed Solution

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Then the solution is :

2x+y=62x+2y+2=10x+y=42x+y=6x=2,y=2

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A mixture of H2(g),N2(g) and O2(g) occupying 10 mL underwent reaction so as to form H2O2(l) and N2H2(g) as the only products causing the volume to contract by 6 mL. The remaining mixture was passed through Pyrogallol causing a contraction of 1 mL. To the remaining mixture excess H2 was added and the above reaction was repeated, causing a reduction in volume of 1 mL. Assuming no older products to be forming calculate the volume of H2 (in mL in the initial mixture.