A modulating signal $2 \sin (6 .28 \times 10^{6})$ t is added to the carrier signal 4sin $(12.56 \times 10^{9}) t$ for amplitude modulation. The combined signal is passed through a non-linear square law device. The output is then passed through a band pass filter. The bandwidth of the output signal of band pass filter will be___MHz.

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answer is 2.

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Detailed Solution

Frequencies present in output of square law device
$2 f_{c}, f_{c} + f_{m}, fc, f_{c} - f_{m}, 2 f_{m}, f_{m}$
After passing through band bass filte.
$f_{c} + f_{m}, f_{c}, f_{c} - f_{m}$
Band width $= 2 f_{m}$
$\begin{array}{l} = \frac{2 ω_{m}}{2 π} = \frac{6 .28 \times 10^{6}}{3 .14} \\ = 2 MHz \end{array}$

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