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Q.

A molecule of a gas has six degrees of freedom. Then the molar specific heat of the gas at constant volume is

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a

$\frac{3 R}{2}$

b

$\frac{R}{2}$

c

$R$

d

$3 R$

answer is D.

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Detailed Solution

Here, number of degrees of freedom, f = 6

Molar specific heat of the gas at constant volume is $C_{V} = \frac{f}{2} R = \frac{6}{2} R = 3 R$

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A molecule of a gas has six degrees of freedom. Then the molar specific heat of the gas at constant volume is