A molecule ${AX}_{2}$ has two lone pairs over A. Its shape is

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Angular

Tetrahedral

Pyramidal

Linear

answer is C.

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It is given around "A" 4 pairs( 2 B.P's and 2 L.P's)are there.
$4 σ$ - bonds as 2 L.p's are considered as $2 σ$ bonds. So, ${sp}^{3}$ hybridization
with two L.P.
Angular shape / V - shape is molecular geometry.

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