A molecule ${\mathrm{XY}}_2$ contains two $\sigma$ bonds, two $\pi$ bonds and one lone pair of electrons in the valence shell of X. The arrangement of lone pair as well as bond pairs is

The valence shell of X has two $\sigma$ bonds and one lone pair of electrons. Thus it has trigonal planar geometry. Remember $\pi$ bonded electrons are not considered while deciding the geometry of the molecule.