A monkey of mass 20 kg is holding a vertical rope. The rope can break when a mass of 25 kg is suspended from it. What is the maximum acceleration with which the monkey can climb up along the rope?

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$7 m s^{- 2}$

$10 m s^{- 2}$

$5 m s^{- 2}$

$2.5 m s^{- 2}$

answer is D.

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Detailed Solution

$\begin{array}{l} \Rightarrow 25 \times 10 = 20 a + 20 \times 10 \\ \Rightarrow a = \frac{25 \times 10 - 20 \times 10}{20} \\ \Rightarrow a = 2.5 m / {sec}^{2} \end{array}$

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