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A monkey of mass 25 kg is holding a vertical rope. The rope does not break, if a body of mass 30 kg is
suspended from it, but the rope breaks, if the mass of the body suspended with the rope exceeds 30 kg. What will be the maximum acceleration with which the monkey can climb up along the rope? (Take, g = 10 $m s^{- 2}$ ) [JCECE 2012]

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4 $m s^{- 2}$

3 $m s^{- 2}$

2 $m s^{- 2}$

25 $m s^{- 2}$

answer is A.

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Detailed Solution

The maximum weight which can be suspended with the rope without breaking it = 30 kg-wt.

or $F_{\max} = 30 \times 10 = 300 N$

$∴ 300 = m g + m a$

$\Rightarrow m a = 300 - m g = 300 - 25 \times 10 = 50 N$

$\Rightarrow a = \frac{50}{m} = \frac{50}{25} = 2 {ms}^{- 2}$

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