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A monkey of mass 40 kg climbs on a massless rope of breaking strength 600 N. The rope will break if the monkey. $(Take g = 10 m / s^{2})$

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Climbs up with a uniform speed of 6 m/s

Climbs down with a uniform speed of 5 m/s

Climbs up with an acceleration of $6 m / s^{2}$

Climbs down with an acceleration of 4 m/s²

answer is B.

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Detailed Solution

T = mg + ma

600 = 40 (g+a)

$g + a = \frac{600}{40} = 15$

a = 15 - 10 = $5 m / s^{2}$ maximum acceleration

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