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A monoacid organic base (0.0915 g) requires 15 ${cm}^{3}$ of N/20 HCl for complete neutralization. The molar mass of

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$61 {g mol}^{- 1}$

$122 g {mol}^{- 1}$

$224 g {mol}^{- 1}$

$183 g {mol}^{- 1}$

answer is B.

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Detailed Solution

A monoacid organic base (0.0915 g) requires 15 ${cm}^{3}$ of N/20 HCl for complete neutralization. The molar mass of $122 g {mol}^{- 1}$

Weight of the organic base/equivalent mass = normality* Volume: milliequivalence of base = milliequivalence of acid

in this case, molar mass = equivalent mass ( as it is monoacid base)
Assuming M is the molar mass, the values 0.0915/M = 1/20* 15/1000 M and 122 g/mol are suitable substitutes.

Hence, option B is correct.

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