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Q.

A monoatomic gas CV=32R is allowed to expand 2 adiabatically and reversibly from initial volume of 8 L at 300 K to a volume V2 at 260 K V2 is :

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a

23 L

b

10.5 L

c

50.5 L

d

8.5 L

answer is A.

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Detailed Solution

It is known that,

T1V1γ1=T2V2γ1; 

Given,

γ=53;

T1=300 K,

V1=8L,

T2=250 K

Put these values in the above equation we get the value of final volume as 10.5 L.

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