A monoatomic ideal gas is following the cyclic process ABCA as given by internal energy (U) versus density  $\rho$ as shown. Choose the correct option (s)

For path AB, TV = constant this implies  $\Rightarrow P{V}^2=$ constant.  Because $m=2$ and for  monoatomic gas  $\gamma =5/3$
 $C=\frac{R}{\gamma -1}-\frac{R}{m-1}=\frac{R}{2}$
For BC it is an isochoric process and temperature is decreasing
For process CA (isothermal) $W=nRT\ln \frac{V_A}{V_C}=\frac{2}{3}{U}_o \ln 4$