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Q.

A monochromatic beam of electrons accelerated by a potential difference V falls normally on the plane containing two narrow slits separated by a distance d. The interference pattern is observed on a screen parallel to the plane of the slits and at a distance of D from the slits. Fringe width is found to be w1. When electron beam is accelerated by the potential difference 4V the fringe width becomes w2. Find the ratio  w1w2 (Given d<<D)

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answer is 2.

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Detailed Solution

: KE of  e=eV=P22me 
 λ=hP=h2eVme
 λ1V
Fringe with is proportional to wave length
 W1W2=V2V1=2

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