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A monochromatic light is incident at a certain angle on an equilateral triangular prism and suffers minimum deviation. If the refractive index of the material of the prism is $\sqrt{3}$ , then the angle of incidence is

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$90^{0}$

$45^{0}$

$60^{0}$

$30^{0}$

answer is A.

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Detailed Solution

$r_{1} = r_{2} = \frac{A}{2} = \frac{60 °}{2} = 30 °$

Using snell’s law at the interface,

1 sin i = $\sqrt{3} \sin r_{1}$

sin i = $\sqrt{3} \sin 30 ° = \sqrt{3} / 2$

i = $60^{0}$

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