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Q.

A monoenergetic electron beam with a de Broglie wavelength of x Å is acceleratred till its wavelength is halved.  By what factor is its kinetic energy changed?

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a

8

b

6

c

3

d

4

answer is C.

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Detailed Solution

λ=h2mE

λE= constant

So λ1E1=λ2E2

λ2/λ1=E2/E1=2

Therefore,  E2/E1=4

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A monoenergetic electron beam with a de Broglie wavelength of x Å is acceleratred till its wavelength is halved.  By what factor is its kinetic energy changed?