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Q.

A motor car is travelling at ${30ms}^{- 1}$ on a circular road of radius 500m . It is increasing speed at the rate of ${2ms}^{-2}$ The acceleration of car is

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answer is 6.

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Detailed Solution

Given $a_{t} = 2 m s^{- 2} a n d a_{r} = \frac{v^{2}}{r} = \frac{30 \times 30}{500} = 1.8 m s^{- 2}$

$∴ a = \sqrt{a_{t}^{2} + a_{t}^{2}} = \sqrt{{1.8}^{2} + 2^{2}} = 2.7 m s^{- 2}$

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