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Q.

A motorcyclist moving with a velocity of 72 km/h on a flat road takes a turn on the road at a point, where the radius of curvature of the road is 20 m. The acceleration due to gravity is 10 m/s2 . In order to avoid sliding, he must bend with respect to the vertical plane by an angle

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a

θ=tan-14

b

θ=45°

c

θ=tan-12

d

θ=tan-16

answer is C.

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Detailed Solution

v = 72 km/h = 72×518 m/s = 20 m/s

tan θ=v2Rg

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