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A movable bridge divides a sonometer wire into two parts which differ in length by 1 cm and produce 4 beats per second when sounded together. If the whole length of the wire is 100 cm, the frequencies of the parts are

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100 Hz, 104 Hz

198 Hz, 202 Hz

206 Hz, 210 Hz

250 Hz, 254 Hz

answer is B.

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Detailed Solution

Two lengths must be $l_{1} = 49 .5 cm and l_{2} = 50 .5 cm$

$\frac{n_{1}}{n_{2}} = \frac{50 .5}{49 .5}$

$Also n_{1} - n_{2} = 4 .$

$Solving we get n_{1} = 202 Hz, n_{2} = 198 Hz$

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