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A moving car is stopped in $10 seconds$ by applying brakes that give a retardation of $2.5 m / s^{2} .$ The initial velocity of the car would be

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25 m / s

15 m / s

20 m / s

None

answer is A.

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Detailed Solution

A moving car is stopped in

10 seconds

by applying brakes that give a retardation of

2.5 m / s^{2} .

The initial velocity of the car would be

25 m / s

.
Given that, car stops after applying brakes, this means that
final velocity

= 0 m / s

acceleration,

a = - 2.5 m / s^{2}

time

t = 10 seconds

Initial velocity

= u

To find out initial velocity,

u

, we can use the equation

v = u + at

0 = u + (- 2.5) 10

u = 25 m / s

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