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A moving car possesses average velocities of 5 ${ms}^{- 1}$ , 10 m/s and 15 m/s in the first, second and third seconds respectively. What is the total distance covered by the car in these three seconds?

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15 m

55 m

30 m

None of these

answer is B.

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Detailed Solution

distance covered = s = $v_{av} \times time$

For 1st second: $S_{1} = 5 \times 1 = 5 m$

For 2nd second : $S_{2} = 10 \times 1 = 10 m$

For 3rd second : $S_{3} = 15 \times 1 = 15 m$

Total distance traveled

$S = S_{1} + S_{2} + S_{3} = 5 + 10 + 15 = 30 m$

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