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A moving coil galvanometer has 100 turns and each turn has an area of $2.0 c m^{2}$ . The magnetic field produced by the magnet is 0.1T and the deflection in the coil is 0.05 radian when a current of 10 mA is passed through it. The torsional constant of the suspension wire is $x \times 10^{- 5} N - m / r a d$ . The value of x is ___.

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answer is D.

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Detailed Solution

Moving Coil Galvanometer Solution

τ = BINA sinφ

At equilibrium: Cθ = BINA sin90°

C = BINA / θ

= (0.1 × 10 × 10⁻³ × 100 × 2 × 10⁻⁴) / 0.05

= 4 × 10⁻⁴ N·m/rad

Given C = x × 10⁻⁵ N·m/rad

⇒ x = 40

Answer: x = 40

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