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A moving coil galvanometer of resistance 100Ω shows full scale deflection when a current of 100 micro
ampere passes through it. If it is intended to show full scale deflection when a current of one milli-ampere passes through it, the value of shunt resistance, to be connected to the galvanometer is

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100/9

900/7

9/4

10/3

answer is C.

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Detailed Solution

$S = \frac{G}{n - 1}, (\begin{array}{l} ∵ i_{g} = \frac{1}{n} i, n = \frac{i}{i_{g}} \\ i = 100 \times 10^{- 6} i_{g} = 10^{- 3} A \\ n = \frac{i}{i_{g}} = \frac{10^{- 3}}{10^{- 4}} = 10 \end{array})$
$s = \frac{100}{10 - 1} = \frac{100}{9}$

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