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A moving coil galvanometer of resistance 100Ω shows full scale deflection when a current of 100 micro ampere passes through it. If it is intended to show full scale deflection when a current of one milli-ampere passes through it, the value of shunt resistance, to be connected to the galvanometer is

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answer is C.

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Detailed Solution

To calculate the shunt resistance, we use the formula:

$R_{s} = \frac{I_{G}}{I - I_{G}} R_{G}$

Given that the resistance of the galvanometer is 100Ω and the full-scale deflection current is 100 micro ampere, we can calculate the shunt resistance as follows:

$R_{s} = \frac{100 \times 10^{- 6}}{10^{- 3} - 100 \times 10^{- 6}} \times 100$

$R_{s} = \frac{100}{9} Ω$

Hence the correct answer is $\frac{100}{9} Ω .$

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