A narrow electron beam passes undeviated through an electric field $E = 3 \times 10^{4}$ volt/m and an overlapping magnetic field $B = 2 \times 10^{- 3} W e b e r / m^{2}$ . If electric field and magnetic field are mutually perpendicular. The speed of the electrons is

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60 m/s

${10.3×10}^{7} m/s$

${1.5×10}^{7} m/s$

${0.67×10}^{-7} m/s$

answer is C.

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Detailed Solution

If electron beam passes undeviated then magnetic force should balance electric force $v= \frac{E}{B} = \frac{3 \times 10^{4}}{2 \times 10^{- 3}} = 1.5 \times 10^{7} m / \sec$

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