Q.

A natural number divisible by ‘11’ is

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a

6545

b

29843

c

80927

d

all

answer is D.

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Detailed Solution

A natural number is divisible by 11, if the difference between the sum of the digits at odd places and the sum of the digits at even places (from the right) is either ‘0’ or divisible by 11

A) In 6545, 6+4=10and5+5=101010=0

Hence 6545 is exactly divisible by 11

B) In 80927, 8+9+7=24and0+2=2242=22

Hence 80927 is exactly divisible by 11

C) In 29843, 2+8+3=13and9+4=131313=0

Hence 29843 is exactly divisible by 11

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A natural number divisible by ‘11’ is