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A natural number divisible by ‘6’ is

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8430

answer is C.

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Detailed Solution

A natural number is divisible by 6, if it is divisible by 2 nad 3

Here, in 8430, units digit is ‘0’ $\to$ 8430 is divisible by 2

Now, $8 + 4 + 3 + 0 = 15 \to$ 8430 is divisible by 3

$∴$ 8430 is exactly divisible by 6

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