A natural number has prime factorization given by n=2x3y5z where y and z are such that y+z=7 and y−1+z−1=712;y>z.Then the no of odd divisors of n including 1, is_____

y+z=7 1y+1z=712 y+zyz=712 y=4,z=3 ∴n=2x3453∴ No of odd divisors = 5×4=20

A natural number has prime factorization given by n=2x3y5z where y and z are such that y+z=7 and y−1+z−1=712;y>z.Then the no of odd divisors of n including 1, is_____

y+z=7 1y+1z=712 y+zyz=712 y=4,z=3 ∴n=2x3453∴ No of odd divisors = 5×4=20

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A natural number has prime factorization given by $n = 2^{x} 3^{y} 5^{z}$ where y and z are such that $y + z = 7$ and $y^{- 1} + z^{- 1} = \frac{7}{12}; y > z$ .Then the no of odd divisors of n including 1, is_____

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$y + z = 7 \frac{1}{y} + \frac{1}{z} = \frac{7}{12} \frac{y + z}{y z} = \frac{7}{12} y = 4, z = 3 ∴ n = 2^{x} 3^{4} 5^{3}$

$∴$ No of odd divisors = $5 \times 4 = 20$

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A natural number has prime factorization given by n=2x3y5z where y and z are such that y+z=7 and y−1+z−1=712;y>z.Then the no of odd divisors of n including 1, is_____

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A natural number has prime factorization given by $n = 2^{x} 3^{y} 5^{z}$ where y and z are such that $y + z = 7$ and $y^{- 1} + z^{- 1} = \frac{7}{12}; y > z$ .Then the no of odd divisors of n including 1, is_____