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Q.

A natural number is chosen at random from the first 100 natural numbers. The probability that $x + \frac{100}{x} > 50$ is

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a

1/10

b

11/50

c

11/20

d

9/10

answer is C.

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Detailed Solution

$\begin{array}{l} n (s) = 100 c_{\begin{array}{l} 1 \end{array}} \\ E \to x + \frac{100}{x} > 50 \\ x^{2} - 50 x + 100 > 0 \\ E \to x + \frac{100}{x} > 50 \\ x = \{1, 2, 48, 49,____100\} \\ n (E) = 55 \\ p (E) = \frac{55}{100} = \frac{11}{20} \end{array}$

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