A negligibly small current is passed though a wire of length 15m & resistance of $5 Ω,$ having uniform cross section of $6 \times 10^{- 7} m^{2},$ then coefficient of resistivity of material is

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$4 \times 10^{- 7} Ω - m$

$1 \times 10^{- 7} Ω - m$

$2 \times 10^{- 7} Ω - m$

$3 \times 10^{- 7} Ω - m$

answer is B.

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Detailed Solution

Length $l = 15 m]$ Resistance $R = 5 Ω$
Cross sectional area $A = 6 \times 10^{- 7}$

$ρ = \frac{RA}{l} = \frac{5 \times 6 \times 10^{- 7}}{15} ∴ ρ = 2 \times 10^{- 7} Ω - m$

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