A network of resistors is connected to a 16 V battery with internal resistance, 1Ω as shown in figure. Voltage drop across CD is

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A network of resistors is connected to a 16 V battery with internal resistance, $1 Ω$ as shown in figure. Voltage drop across CD is

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4 V

8 V

2 V

6 V

answer is C.

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Detailed Solution

Effective resistance in the circuit is

$R_{eff} = \frac{4 \times 4}{4 + 4} + 1 + \frac{12 \times 6}{12 + 6} + 1 = 8 Ω$

Current in the circuit is

$I = \frac{V}{R_{eff}} = \frac{16}{8} = 2 A$

P.D across CD is

$V = IR = 2 \times \frac{12 \times 6}{12 + 6} = 8 V$

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