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Q.

A neutral particle of mass 28 g is at rest in a uniform magnetic field B=2003T.  At t=0, particle decays into two particle of equal mass and one of them having charge  3μC. Both of them move in separate paths lying in the plane perpendicular to magnetic field B. At later time t, the particle collides (neglecting the interaction force). Calculate t100

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answer is 2.2.

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Detailed Solution

t=T2=πmqB=(227)×(14×103)(3×106)(200/3)=220s

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