A neutral white salt of sodium (P) on heating liberates a gas leaving a highly alkaline residue ‘Q’.
The gas ‘A’ is colourless, odour less and turns a solution of milky. Then

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${P is NH}_{4} {HCO}_{3}$

${Q is Na}_{2} {CO}_{3}$

${P is NaHCO}_{3}$

${A is CO}_{2}$

answer is A, B, C.

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Detailed Solution

$\underset{P}{N a H C O_{3}} \overset{Δ}{\to} \underset{Q}{N a_{2} C O_{3}} + \underset{A}{C O_{2}} + H_{2} O \overset{C a {(O H)}_{2}}{\to} \underset{W h i t e p p t}{C a C O_{3}} ↓$

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