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A newspaper placed nearer than $50 cm$ cannot be read by a person. What will be the power of the corrective lens required?

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- 0.25 D

+ 2.5 D

+ 2 D

- 0.5 D

answer is C.

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Detailed Solution

The power of the corrective lens required is

+ 2 D

.
Given,
Focal length

f = 50 cm

It is known that the power of a lens is the reciprocal of the focal length of the lens. Mathematically,

P = \frac{100}{f}

Where

f

is the focal length of the lens in centimetres
On substituting the given values, we get the power as

\Rightarrow P = \frac{100}{50}

\Rightarrow P = 2 D

Hence, the power of the lens required is

2 D

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