A non - volatile solute (A) is dissolved in a volatile solvent (B). The vapour pressure of resultant solution is $P_{S}$ .The vapour pressure of pure solvent is $P_{B}^{°}$ . If X is the mole fraction , then the correct one of the following is

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P_{B}^{0} = P_{S} \cdot X_{B}

P_{S} = P_{B}^{0} \cdot X_{B}

P_{S} = P_{B}^{0} \cdot X_{A}

P_{B}^{0} = P_{S} \cdot X_{A}

answer is C.

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Detailed Solution

If a solution has a non volatile solute in a volatile solvent then the vapor pressure of resultant solution depends on mole fraction of solvent present in it.Vapour pressure of solution,

P_{S} = P_{B}^{0} . X_{B}

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