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A non-conducting spherical shell of diameter IO cm has a charge of $1.6 x 10^{- 4} C$ and a charge of 20 C is placed at a distance of I0 cm from the centre then force between the two will be :

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$4 x 10^{9} N$

$16 x 10^{13} N$

$3 x 10^{9} N$

$6 x 10^{- 9} N$

answer is C.

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Detailed Solution

$F = \frac{kQq}{r^{2}} = \frac{9 x 10^{9} x 20 x 1.6 x 10^{- 4}}{{(10 x 10^{- 2})}^{2}} = 3 x 10^{9} N$

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