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A non-standard vernier callipers has 10 V.S.D coinciding with 7 M.S.D, with each M.S.D equal to 1 mm. The scale has a maximum measurable length of 100 MSD. If 14th M.S.D. is found to coincide with 4th V.S.D, where does the zero of vernier lie? Assume no zero error.

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Between 10th and 11th M.S.D.

Between 11th and 12th M.S.D.

Between 9th and 10th M.S.D.

Exactly on the 10th MSD

answer is B.

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Detailed Solution

1 VSD = 0 .7 MSD
4 VSD = 2.8 MSD

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