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Q.

A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the Binding Energy in the process is :

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a

0.9 MeV

b

9.4 MeV

c

804 MeV

d

216 MeV

answer is A.

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Detailed Solution

Final total binding energy
= 2 × 8.5 × 120 MeV = 2040 MeV
Initial total binding energy
= 240 × 7.6 MeV = 1824 MeV
Gain = (2040 - 1824) MeV = 216 MeV

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