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Q.

A nucleus with mass number 242 and binding energy per nucleon as 7.6 MeV breaks into two fragment each with mass number 121. If each fragment nucleus has binding energy per nucleon as 8.1 MeV, the total gain in binding energy is ________MeV.

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answer is 121.

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Detailed Solution

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BEX=242×7.6MeV=1839.2 MeVX→2YBEY=121×8.1MeV=980.1 MeVQ=2BEY−BEX=121 MeV

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A nucleus with mass number 242 and binding energy per nucleon as 7.6 MeV breaks into two fragment each with mass number 121. If each fragment nucleus has binding energy per nucleon as 8.1 MeV, the total gain in binding energy is ________MeV.