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A nugget of gold and quartz was found to contain x g of gold and y g of quartz and has density d. If the densities of gold and quartz are $d_{1}$ and $d_{2}$ respectively, then the correct relation is:

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$x d_{1} + y d_{2} = (x + y) d$

$\frac{x + y}{d} + \frac{x}{d_{1}} + \frac{x}{d_{2}} = 0$

$\frac{x}{d_{2}} + \frac{y}{d_{1}} = \frac{x + y}{d}$

$\frac{x}{d_{1}} + \frac{y}{d_{2}} = \frac{x + y}{d}$

answer is A.

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Detailed Solution

$Density = \frac{Mass}{V olume}$

So, in 1L of gas, 0.178 mass is present. Therefore, vapour density $= \frac{M}{2}$

= 0.089

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