A number exceeds it’s four - seventh by 18 what is the number

$\begin{array}{l}letthenumberbex\\ \frac{4}{7}oftheno=\frac{4}{7}ofx\\ =\left(\frac{4}{7}\right)x\Rightarrow \frac{4x}{7}\\ Accordingtotheproblem\\ x=\frac{4x}{7}+18\\ x-\frac{4x}{7}=18\\ \Rightarrow \frac{7x-4x}{7}=18\\ \frac{3x}{7}=18\\ 3x=126\\ x=\frac{126}{3}\\ thenumber=42\end{array}$