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Q.

A number of carbon atoms in 1 g of $C a C O_{3}$ is

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a

6.023 \times 10^{23}

b

3.0125 \times 10^{22}

c

1.204 \times 10^{23}

d

6.023 \times 10^{21}

answer is B.

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Detailed Solution

100g of

C a C O_{3}

contains

6.023 \times 10^{23}

Carbon atoms

1 g of $C a C O_{3}$ contains $\to$ x atoms

$x = \frac{6.023 \times 10^{23}}{100} = 6.023 \times 10^{21}$ Carbon atoms.

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A number of carbon atoms in 1 g of CaCO3 is