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$A \overset{O_{2}}{\to} B +$ other product(s)
‘A’ is complex ion of $C o^{2 +}$ with six $N O_{2}^{-}$ ligands. Then identify the correct statement(s) regarding complex ion of B.

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Complex ion of B exhibit linkage isomerism

In the complex ion of B, Cobalt is in +3 oxidation state

Complex ion of B is paramagnetic

Complex ion of B is a high spin complex

answer is A, C.

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Detailed Solution

(i) A is ${[C o^{I I} {(N O_{2})}_{6}]}^{4 -}$ and B is ${[C o^{I I I} {(N O_{2})}_{6}]}^{3 -}$

(ii) $N O_{2}^{-} :$ ambidentate ligand and strong field ligand

(iii) $C o^{3 +}$ with SFL : $d^{6} : t_{2 g}^{6} e_{g}^{0}$

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